Chemistry Forum

Hey You see that if we are not specified with number of moles, we can see that the equation would be CH4 + 2 O2 = CO2 + 2 H2O Now you see every 1 mole of CH4 must react with 2 moles of O2 to give 1 mole of CO2 and two moles of H2O. So CH4 Is half than oxygen. ANd CO2 is half than H2O But we have 2 m...

Hey Umm i dont know about the second one lol but for the first one that is for sure correct, which is C4H10O + HCl = C4H9Cl + H2O and for the second one, isnt it also including NaOH on reactants side..?? Umm If you do include NaOH, it would give you an acetic acid like you suggested and an alchol so...

Hey
You equation would be hope that helps,

Hmm
for the first one, you would just get an ionic form of the compound which would be a dissociation reation such as:
Ba(OH)2 + H2O = Ba(2+) + OH(-) +H2O
Barium Hydroxide is strong base but it is moderately soluble in water.

2)
2 HNO3 + Ba(OH)2 = Ba(NO3)2 + 2 H2O

Hope that helps,

Yeah density would be mass divided by volume in ur case (in gms per litre ur case) use PV= nRT where n is number of moles which is equal to (mass m/molar mass M) so you have PV= (m/M)RT Rearranging you would get PM= (m/V)RT m/V is density (d) so you can write PM= dRT or again rearranging d= PM/RT no...

hey from wut think you shud be making a copper hydroxide Cu(OH)2 as you have no chances of making CuSO4 and sulfuric acid and Mg metal as:
hope that helps,

Hey milZ1,
I would say the other product would be amonium nitrate besides Aluminium(III) acetylacetonate as you have suggested.. hope that helps,

hey the balanced equation should look like if Na2CO3 is solid 2HCl + Na2CO3 (s) = 2NaCl + H2O + CO2 but in ur case it is aquous which affect the overall reaction and it should rather look like: Na2CO3 (aq) + HCl (aq) = NaHCO3 (aq) + NaC...

Hey
And your main part of the question, you see that mole ratio of NaHCO3 and CO2 is 1 : 1 which means same number of moles of both molecules.
Moles of NaHCO3 = 2gm / 84.01 gm/mol
= 0.0238 moles of NaHCO3

Which means how many moles of CO2??? lol

hope this helps,

Hey the balanced reaction would be
NaHCO3 + H2O = H2CO3 + NaOH
where H2CO3 further decomposes to CO2 and H2O so overall reaction looks sumting like
NaHCO3 + H2O = H2O + CO2 + NaOH
Hope that helps,

Hey,
CaCl2 + 2 H2O → CaCl2·2H2O

Hey,
Almost right but have problem with the valency of Ca so it should rather be:
Ca(HCO3)2 + 2 NaC18H35O2 = Ca(C18H35O2)2 + 2 NaHCO3

hope this helps.

Hey,

H2O + NaC18H35O2 = C18H36O2 + NaOH

Hope this helps,

what i meant to say was
"It could be either one you just have to make sure that if you are considering stock solution as M1, V1 has to be the volume of the stock solution or vice versa. sorryy again...

I hope I answered your question lol.