EQUATION HELP!!!!! PLEASE!!!!

milZ1 · Post by **milZ1** » Sat Apr 26, 2008 7:39 pm

Hey,

My question is if you dissolve aluminium nitrate nonahydrate in water and add acetylacetone. Then slowly add ammonia till the solution is alkaline to form the product tris(acetylacetonato)aluminium(III).

What is the eqaution, I don't know what to include in the equation and can't balance it????

Al(NO₃)₃.9H₂O + H₂O + C₅H₈O₂ + NH₃ = Al(C₅H₇O₃)₃

Thank you in advance,

Mili....

milZ1 · Post by **milZ1** » Wed Apr 30, 2008 3:52 am

Hey Does anyone know the answer to this question please?????????????????? It's really urgent, thank you!!!

Zedekiah · Post by **Zedekiah** » Thu May 01, 2008 6:01 pm

As I understand it, the ammonia is just to promote the coordination of the acetylacetone. Since the ammonia doesn't really do anything, you may just want to write it above the reaction arrow.

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Al&#40;NO3&#41;3 + 3C5H8O2 ---->  &#91;Al&#40;C5H8O2&#41;3&#93;&#40;NO3&#41;3

That looks about right... nitrate is a spectator ion, you can scrub that as well.

sharan · Post by **sharan** » Sat May 03, 2008 11:39 am

Hey milZ₁,
I would say the other product would be amonium nitrate besides Aluminium(III) acetylacetonate as you have suggested..

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4 Al&#40;NO3&#41;39H2O + 53 H2O + 12 C5H8O2 + 186 NH3 = 4 Al&#40;C5H7O3&#41;3 + 171 NH4NO3

hope that helps,