Chlorine Hydrate

[zanbr]

Cl₂(g) + 7.3 H₂O(l) → Cl₂ · 7.3 H₂O(s)

Is this equation right? In laboratory I made chlorine gas and then the gas flowed to a bottle with ice water where the chlorinehydrates were formed. The title of the experiment is indeed Cl₂* 7.3 H₂O so this has to be the product.

Thanks for your help!

[ChenBeier]

No, chlorine reacts with water to hydrochloric acid HCl and hypochlorous acid HClO although hydrates are reported at low temperature.

Cl₂ + H₂O => HCl + HClO

It's chlorine not Chloride.

http://www.researchtrends.net/tia/artic ... 6&aid=3813

[zanbr]

I actually did this equation in the third step. This is the whole procedure:

2 KMnO₄ (s)+ 16 HCl(l)→ 5 Cl₂(g)+ 2 MnCl₂(aq) + 2 KCl(aq) + 8 H₂O(l)
Cl₂(g) + 7.3 H₂O(l) → Cl₂ · 7.3 H₂O(s)
Cl₂(g)+ H₂O(l)→ HCl(aq)+ HOCl(aq)

And because there is Cl₂ · 7.3 H₂O formed, I thought I have to write an equation about this in the protocol

[ChenBeier]

Why do you think it's 7.3 H₂O.
In Literature the mixtures are different.

https://www.nature.com/articles/151309a0

[zanbr]

It was in my script like this.