In a problem they give me an initial reaction that I have to complete and balance, after that put the complete ionic equation and the net ionic equation.
AgBr (s) + BaCl2 (aq) →
Molecular equation.
AgBr (s) + BaCl2 (aq) → AgCl2 (s) + BaBr (aq)
Complete ionic equation.
AgBr (s) + Ba+2 (aq) + Cl2-1 (aq) → AgCl2 (s) + Ba+2 (aq) + Br-2 (aq)
Spectator ions: Ba + 2 (ac)
AgBr (s) + Ba+2 (aq) + Cl2-1 (aq) → AgCl2 (s) + Ba+2 (aq) + Br-2 (aq)
Net ionic equation.
AgBr (s) + Cl2-1 (aq) → AgCl2 (s) + Br-2 (aq)
It's okay like that? I have doubts if a solid state (s) is found in the reactants and another solid state is in the products, if the molecular ion and net ionic equations can be performed.
I appreciate if anyone can help me.
Complete ionic equation and net ionic equation
Moderators: Xen, expert, ChenBeier
All bromides are soluble except Ag+, Pb+2, Hg2 +2 halides, the compound 2AgBr (s)
All chlorides are soluble, except Ag+, Pb+2, Hg2 +2 halides, the compound 2AgCl (s)
The correct balance of the equation would be this?
2AgBr (s) + BaCl2 (aq) = 2AgCl (s) + BaBr2 (aq)
Oxidation number.
BaCl2 (aq)
Ba +2
Cl2 -1
2AgBr (s)
Ag +1
Br -1
2AgCl (s)
Ag +1
Cl -1
BaBr2 (aq)
Ba +2
Br2 -1
When i can identify the balanced equation, i will be able to do the complete ionic equation and the net ionic equation.
All chlorides are soluble, except Ag+, Pb+2, Hg2 +2 halides, the compound 2AgCl (s)
The correct balance of the equation would be this?
2AgBr (s) + BaCl2 (aq) = 2AgCl (s) + BaBr2 (aq)
Oxidation number.
BaCl2 (aq)
Ba +2
Cl2 -1
2AgBr (s)
Ag +1
Br -1
2AgCl (s)
Ag +1
Cl -1
BaBr2 (aq)
Ba +2
Br2 -1
When i can identify the balanced equation, i will be able to do the complete ionic equation and the net ionic equation.