Author Message

Newbie

Joined: 09 Sep 2018
Posts: 4

I am not sure if I have solved this correctly.

Sb (OH)3 +Na2S --- SbS3

I have attempted to check my answer, but I can't find it online.

Thank you!!!!!

Distinguished Member

Joined: 27 Sep 2017
Posts: 269
Location: Berlin, Germany
 The equation is not balanced. On left side and right side the number of atoms must be equal. Check also oxidation number of stibium. Try again.

Newbie

Joined: 09 Sep 2018
Posts: 4

Thank you

The lab required Sb3+

Sb OH3 + Na2 S-----2SbS3 +2Na OH3

I have a problem grasping is it the total number of charges that need to be equal on both sides?

Distinguished Member

Joined: 27 Sep 2017
Posts: 269
Location: Berlin, Germany
 It is still wrong. Try to balance first Sb3+ with S2- What do you get?

Newbie

Joined: 09 Sep 2018
Posts: 4

Think I got it!

I think I have it LOL

SbOH3 + Na2S-----Sb + NaOH

Distinguished Member

Joined: 27 Sep 2017
Posts: 269
Location: Berlin, Germany
 No In Sb3+ + S2- , we have 3+ and 2- . Like in mathematics 1/3 and 1/2 you have to go 6. 2 * 3+ = -(3* 2-) 2 Sb3+ + 3 S2- => Sb2S3 With your compounds it means 2 Sb(OH)3 + 3 Na2S => Sb2S3 + 6 NaOHLast edited by ChenBeier on Sun Sep 09, 2018 12:23 pm; edited 1 time in total

Newbie

Joined: 09 Sep 2018
Posts: 4

Thank you

Thank you for your help. I see how you solved it and I will practice more.

Newbie

Joined: 07 Oct 2018
Posts: 2

 reddnwaiting wrote: I am not sure if I have solved this correctly. Sb (OH)3 +Na2S --- SbS3 I have attempted to check my answer, but I can't find it online. Thank you!!!!!

2Sb(OH)3(s)+3NA2S(ac)=SB2S3(s)+6NaOH(ac)

-Sb has +3
-S has -2
-Na has+1
-OH has -1

Distinguished Member

Joined: 27 Sep 2017
Posts: 269
Location: Berlin, Germany
 The problem was solved already above.
 Display posts from previous: All Posts1 Day7 Days2 Weeks1 Month3 Months6 Months1 Year Oldest FirstNewest First
Page 1 of 1