An organic compound contains C, H, N, and O. Combustion of 0.1023 g of the compound in excess oxygen yielded 0.2766 g of CO2 and 0.0991 g of H2O. A sample of 0.4831 g of the compound was analyzed for nitrogen by the Dumas method. At STP, 27.6 mL of dry N2 was obtained. In a third experiment the density of the compound as a gas was found to be 4.02 g/L at 127 ºC and 256 torr. What are the empirical formula and the molecular formula of the compound?
I started to solve the above problem doing the following steps:
- converted 0.2766 g of CO2 to x number of moles of CO2
- converted 0.0991 g of H2O to y number of moles of H2O
- substituted x and 2y into the compound CxH2yNO (since x C atoms go over in front of CO2, and y/2 atoms go over in front of H2O in a combustion reaction.
I am not sure what to do next and how to use the information from the rest of the problem to find out the compound empirical and molecular formula.
Thank you,
Mary
Molecular formula
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Re: Molecular formula
Here is the plan how to solve that:Mary wrote:An organic compound contains C, H, N, and O. Combustion of 0.1023 g of the compound in excess oxygen yielded 0.2766 g of CO2 and 0.0991 g of H2O. A sample of 0.4831 g of the compound was analyzed for nitrogen by the Dumas method. At STP, 27.6 mL of dry N2 was obtained. In a third experiment the density of the compound as a gas was found to be 4.02 g/L at 127 ºC and 256 torr. What are the empirical formula and the molecular formula of the compound?
I started to solve the above problem doing the following steps:
- converted 0.2766 g of CO2 to x number of moles of CO2
- converted 0.0991 g of H2O to y number of moles of H2O
- substituted x and 2y into the compound CxH2yNO (since x C atoms go over in front of CO2, and y/2 atoms go over in front of H2O in a combustion reaction.
Thank you,
Mary
1) From the mass of CO2 calculate mass percent of C in the compound.
2) From the mass of H2O calculate mass percent of H in the compound.
3) From the volume of N2 calculate mass percent of N in the compound.
4) Mass percent of O is 100% minus mass percents of C,H,N.
5) From the density T and P (4.02 g/L at 127 ºC and 256 torr) calculate the molecular weight.
6) Multiply the molecular weight by the (mass percent/100%) for an atom and divide by the atomic weight of this atom to get coefficient in the molecular formula.