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7.41g of M(OH)2 is neutralized by adding a solution that contains 7.30g of hydrochloric acid. Identify metal M.
I have spent hours and hours trying to figure this one out - without success. I presume M must be a Group II alkali and have tried working out what is it using relative atomic masses and moles but am losing the will to live.
hey umm you can try something like..
u can use the fact that since M is group two element
The molecular equation would be
M(OH)2 + 2HCl=> MCl2 + 2H2O
Mole ratio of M(OH)2 to HCl is 1:2
den you can say
2* [7.41/34+M] = 1* 7.30 / 36.5 Since Moles=Mass/ molecular mass
M= 40.1 which is exacly Ca with atomic number 20 and it is group 2 element
hope that helpsss..
hey umm arent you just given with the mass or if you are talking about molecular mass ..
its M(OH)2 which is M+2*O+2*H M is unknown O is 16 and H is 1 so you get 34+M orr if you are also given with M which is Ca with mass 40 you get 34+40 which is 73 approx.
7.41g of M(OH)2 is neutralized by adding a solution that contains 7.30g of hydrochloric acid. Identify metal M.
