7.41g of M(OH)2 is neutralized by adding a solution that contains 7.30g of hydrochloric acid. Identify metal M.
I have spent hours and hours trying to figure this one out - without success. I presume M must be a Group II alkali and have tried working out what is it using relative atomic masses and moles but am losing the will to live.
Any help would be really appreciated.
Many thanks.
Bon03
M(OH)2 + 2HCI = MCl + 2H2O how can I find what M is? Please
Moderators: Xen, expert, ChenBeier
hey umm you can try something like..
u can use the fact that since M is group two element
The molecular equation would be
M(OH)2 + 2HCl=> MCl2 + 2H2O
Mole ratio of M(OH)2 to HCl is 1:2
den you can say
2* [7.41/34+M] = 1* 7.30 / 36.5 Since Moles=Mass/ molecular mass
M= 40.1 which is exacly Ca with atomic number 20 and it is group 2 element
hope that helpsss..
u can use the fact that since M is group two element
The molecular equation would be
M(OH)2 + 2HCl=> MCl2 + 2H2O
Mole ratio of M(OH)2 to HCl is 1:2
den you can say
2* [7.41/34+M] = 1* 7.30 / 36.5 Since Moles=Mass/ molecular mass
M= 40.1 which is exacly Ca with atomic number 20 and it is group 2 element
hope that helpsss..
What is M - thanks Sharan
Sharan
Many many thanks.
Last edited by bon03 on Mon Feb 04, 2008 9:10 am, edited 1 time in total.