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peanot
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Joined: Tue Oct 30, 2007 12:23 pm

PLEASE HELP ME

Post by peanot »

What is the molarity of NaOH solution if 22.5mL of .365M H2SO4 are needed to neutralize 50.00 mL of base. I have to balance the equation before doing the calculations, but I don't know how to, please help!! The products are sodium sulfate and water.
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peter
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Re: PLEASE HELP ME

Post by peter »

peanot wrote:What is the molarity of NaOH solution if 22.5mL of .365M H2SO4 are needed to neutralize 50.00 mL of base. I have to balance the equation before doing the calculations, but I don't know how to, please help!! The products are sodium sulfate and water.
First you need tow rite a balanced equation of the neutralization reaction:

Code: Select all

2NaOH + H2SO4 = Na2SO4 + 2H2O
Then compute the number of moles of H2SO4.
n(H2SO4) = .365M * (22.5/1000) L
Now you can find the number of moles of NaOH:
n(NaOH) = 2*n(H2SO4)
and finally the molarity:
mu(NaOH) = n(NaOH)/V(NaOH)

~peter
Chemistry Legend
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