PLEASE HELP ME
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PLEASE HELP ME
What is the molarity of NaOH solution if 22.5mL of .365M H2SO4 are needed to neutralize 50.00 mL of base. I have to balance the equation before doing the calculations, but I don't know how to, please help!! The products are sodium sulfate and water.
Re: PLEASE HELP ME
First you need tow rite a balanced equation of the neutralization reaction:peanot wrote:What is the molarity of NaOH solution if 22.5mL of .365M H2SO4 are needed to neutralize 50.00 mL of base. I have to balance the equation before doing the calculations, but I don't know how to, please help!! The products are sodium sulfate and water.
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2NaOH + H2SO4 = Na2SO4 + 2H2O
n(H2SO4) = .365M * (22.5/1000) L
Now you can find the number of moles of NaOH:
n(NaOH) = 2*n(H2SO4)
and finally the molarity:
mu(NaOH) = n(NaOH)/V(NaOH)
~peter
Chemistry Legend