Chemistry Forum

Hi can somebody help me with this problem please?

If i have 60% Fe what is its FeO and Fe₂O₃ equivalent in % form?

Thank you.

Calculate % of Fe separately in pure FeO (= A%) and Fe₂O₃ (= B%)
After that combine fractions of each (x and y) to make 60%

xA + yB = 60

x:y ratio now is proportional to the weight ratio of Fe in FeO and Fe₂O₃.
To recalculate to molar ratio you have to divide y by 2 since one molecule of Fe₂O₃ contains two Fe
the molar ratio FeO ; Fe₂O₃ is x : y/2