I've been working for hours on a problem about molar fractions.
The problem is: You have a solution of ethanol and wather. You know that X(eth)=0,90 and you want to calculate its % M/M (masse/masse pourcentage) in the current solution.
How do you solve this?
I've worked with the molar fraction equation: X(eth)= n(eth) / n(eth)+n(w) and found:
m(eth)=9n(eth)m(w) / n(w)
and
m(w)=n(w)m(eth) / 9n(eth)
but that doesn't help me much...
If I use these 2 answers in my % M/M formula, I end up with:
% M/M(eth) = 9n(eth) / n(w)m(eth) X 100
wich is, in fact, = 1/m(w)
And I'm still far from any kind of answer :S
Need help with a problem about molar fractions
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Re: Need help with a problem about molar fractions
Assume you have just 1 mole of the mixture:Killy wrote:I've been working for hours on a problem about molar fractions.
The problem is: You have a solution of ethanol and wather. You know that X(eth)=0,90 and you want to calculate its % M/M (masse/masse pourcentage) in the current solution.
How do you solve this?
I've worked with the molar fraction equation: X(eth)= n(eth) / n(eth)+n(w) and found:
m(eth)=9n(eth)m(w) / n(w)
and
m(w)=n(w)m(eth) / 9n(eth)
but that doesn't help me much...
If I use these 2 answers in my % M/M formula, I end up with:
% M/M(eth) = 9n(eth) / n(w)m(eth) X 100
wich is, in fact, = 1/m(w)
And I'm still far from any kind of answer :S
m(total) = M(eth) * 0.9 + M(w) * 0.1
m(eth) = M(eth) * 0.9
where M - stands for molar weight and m - for actual mass
You need to find mass percent, that is:
m(eth)/m(total)*100% = (M(eth) * 0.9) / (M(eth) * 0.9 + M(w) * 0.1) * 100%
That's it!
Just substitue molar weights and do the math.