Chemistry Forum

KMnO₄ + CrI₂ = MnO₂ + Cr(OH)₃ + KIO

MnO₄- + 2 H₂O + 3 e- => MnO₂ + 4 OH-
Cr 2+ 3 OH- => Cr(OH)₃ + e-
2 I- + 4 OH- => 2 IO- + 2 H₂O + 4 e-

Addition of Oxidation

Cr 2+ + 2 I- + 7 OH- => Cr(OH)₃ + 2 IO- + 5 e- + 2 H₂O

KGV of electrons is 15
5 MnO₄- + 10 H₂O + 15 e- => 5 MnO₂ + 20 OH-

3 Cr 2+ + 6 I- + 21 OH- => 3 Cr(OH)₃ + 6 IO- + 15 e- + 6 H₂O


Addition of Reduction
5 MnO₄- + 4 H₂O + 3 Cr 2+ + 6 I- + OH- => 5 MnO₂ + 3 Cr(OH)₃ + 6 IO-

Add of spectator Ion K+
5 KMnO₄ + 4 H₂O + 3 CrI₂ + KOH => 5 MnO₂ + 3 Cr(OH)₃ + 6 KIO

Finished

Very easy to understand and extremely detailed
bob the robber