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Balance chemical reaction
Posted: Fri Dec 13, 2024 1:11 am
by dashamshn
Sn + NaNO3 -> SnO2 + NaN02
Equalize the reactions using the electron balance method, label the oxidizing agent and reducing agent
Re: Balance chemical reaction
Posted: Fri Dec 13, 2024 2:04 am
by ChenBeier
What are your ideas.
Final is
Sn + 2 NaNO3 => SnO2 + 2 NaNO2
Re: Balance chemical reaction
Posted: Sat Feb 08, 2025 1:39 am
by ChenBeier
Divide by 2 is the result already given.
Re: Balance chemical reaction
Posted: Mon Feb 17, 2025 9:39 pm
by michaeljordan
Sn + 2 NaNO 3 => SnO 2 + 2 NaNO 2 is the most accurate.
Re: Balance chemical reaction
Posted: Tue Feb 18, 2025 1:01 am
by ChenBeier
Why repetition. It's already written above.
Re: Balance chemical reaction
Posted: Wed Feb 19, 2025 11:06 am
by jebeloy
copper(1) sulfate + sodium chloride
Re: Balance chemical reaction
Posted: Wed Feb 19, 2025 11:34 am
by ChenBeier
Copper(I)sulfate is not existing.
The equilibrium is on left right side
Cu2SO4 =======> CuSO4 + Cu
Re: Balance chemical reaction
Posted: Mon Feb 24, 2025 8:49 pm
by saun
To balance the given chemical reaction using the electron balance method, we first need to identify the oxidation states of the elements involved and determine which species are being oxidized and which are being reduced. The reaction is:
Sn+NaNO3→SnO2+NaNO2
Step 1: Assign oxidation states
Sn: In its elemental form, Sn has an oxidation state of 0. In SnO2SnO2, Sn has an oxidation state of +4.
Na: In NaNO3NaNO3 and NaNO2NaNO2, Na has an oxidation state of +1.
N: In NaNO3NaNO3, N has an oxidation state of +5. In NaNO2NaNO2, N has an oxidation state of +3.
O: Oxygen has an oxidation state of -2 in both compounds.
Step 2: Identify the oxidizing and reducing agents
Sn is being oxidized from 0 to +4 (loses 4 electrons).
N in NaNO3NaNO3 is being reduced from +5 to +3 (gains 2 electrons).
Thus:
Oxidizing agent: NaNO3NaNO3 (causes oxidation by accepting electrons).
Reducing agent: SnSn (causes reduction by donating electrons).
Step 3: Balance the electrons
Sn loses 4 electrons: Sn→Sn4++4e−Sn→Sn4++4e−.
Each N in NaNO3NaNO3 gains 2 electrons: N5++2e−→N3+N5++2e−→N3+.
To balance the electrons, we need 2 N atoms to accept 4 electrons (since 2 × 2 = 4). Therefore, we need 2 NaNO3NaNO3 molecules.
Step 4: Write the balanced equation
Sn+2NaNO3→SnO2+2NaNO2
Step 5: Verify the balance
Sn: 1 on both sides.
Na: 2 on both sides.
N: 2 on both sides.
O: 6 on both sides.
The equation is balanced.
Final Answer:
Sn+2NaNO3→SnO2+2NaNO2
Oxidizing agent: NaNO3NaNO3
Reducing agent: SnSn
Re: Balance chemical reaction
Posted: Mon Feb 24, 2025 10:55 pm
by ChenBeier
The answer was already given above. No need to repeat it.