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reaction formula
Posted: Fri Nov 22, 2024 7:19 am
by somayeh932
I want to titrate soil containing manganese oxide using the titration method in the presence of sodium oxalate, sulfuric acid, and water, with permanganate as the titrant, to determine its purity. Can you help me write the reactions and balanced reactions?
Re: reaction formula
Posted: Fri Nov 22, 2024 7:51 am
by Benzene
Hello somayeh932!
Balanced reaction:
MnO2 + MnO4^- + H^+ → Mn^2+ + 8 H2O + O2 + 2 H2O + e-
Charge Balance:
MnO2: Mn^4+ (charge: +4)
MnO4^-: Mn^7+ (charge: +7), O^2- (charge: -2) =>
total charge: +5
H^+: +1
Mn^2+: +2
8 H2O: neutral
O2: neutral
2 H2O: neutral
To balance the charge, we need to add more electrons to the right side of the equation. We can do this by adding 1 (one) electron to the Mn^2+ ion:
This ensures the conservation of both mass and charge.
Bye,
Benzene
Re: reaction formula
Posted: Fri Nov 22, 2024 8:05 am
by ChenBeier
Equation is wrong. Charges not balanced.
Only half equation have electrons. A balanced one has no.
And the method is different. First a known excess amount of oxalate react with MnO2 in the sample.
MnO2 + C2O4 2- + 4 H+ => Mn 2+ + 2 CO2 + 2 H2O
The rest of the oxalate will be titrated with permanganate
2 MnO4- + 5 C2O4 2- + 16 H+ => 2 Mn 2+ +10 CO2 + 8 H2O
The difference of the known amount minus titrated amount of oxalat gives the result.