Page 1 of 1
How to calculate values through graphs
Posted: Thu Mar 21, 2024 3:28 am
by lopuna3
Slowly add Ba(OH)2 solution and solution containing m grams of mixture of Al2(SO4)3 and AlCl3. The dependence of the precipitation mass (y game) on the number of moles of Ba(OH)2 (x mol) is shown graphically. So what is the value of m?
Re: How to calculate values through graphs
Posted: Thu Mar 21, 2024 5:59 am
by ChenBeier
Al2(SO4)3 + 3 Ba(OH)2 => 3 BaSO4 + 2 Al(OH)3
2 AlCl3 + 3 Ba(OH)2 => 3 BaCl2 + 2 Al(OH)3
Aluminiumsulfate will give a precipitate of BaSO4 and Aluminiumhydroxid, Aluminiumchlorid will only give a precipitate of Aluminiumhydroxide.
In the first equation correspond x Ba(OH)2 to x *2/3 Al(OH)3 and to x BaSO4.
The hydroxide correspond to 1/3 Al2(SO4)3
In second equation with y Ba(OH)2 we get also y*2/3 Al(OH)3 and this correspond also to 2/3 AlCl3
1 Ba(OH)2 => 2/3*(x+y) Al(OH)3 + x BaSO4
Ba(OH)2 => x* 1/3 Al2(SO4)3 + y* 2/3 AlCl3