Chemistry Forum

Hello;
I am trying to synthesize sodium hydroxymethanesulfonate from formaldehyde and sodium metabisulfite.

I know that when sodium metabisulfite dissolve in water it gives sodium bisulfite
Na₂S₂O₅ + H₂O → 2 Na + 2 HSO₃

Then how can i synthesize sodium hydroxymethanesulfonate with 37% formaldehyde solution.

Thank you.

You mix equimolar amount of bisulfite powder and formaldehyde. Let it crystallize under a good ventilated hood.

NaHSO₃ + CH₂O => HOCH₂- SO₃ Na

It can be produced also as byproduct from Dithionite

https://en.m.wikipedia.org/wiki/Rongalite

The reaction of sodium metabisulfite with water yields sodium bisulfite, as I am aware.
run 3

Thats is written above already.

ChenBeier wrote: ↑Wed Mar 20, 2024 3:37 amIt can be produced also as byproduct from Dithionite

https://en.m.wikipedia.org/wiki/Rongalite

Dear ChenBeier thank you for your reply.
Rongalite is a Sodium hydroxymethanesulfinate, I am trying to produce sodium hydroxymethanesulfonate.

Can I produce sodium hydroxymethanesulfonate from dithionite?

Read again the Article, you get both.

ChenBeier wrote: ↑Wed Mar 27, 2024 5:06 am Read again the Article, you get both.

Got it @ ChenBeier.

Na₂S₂O₄ + 2 CH₂O + H₂O → HO-CH₂-SO₃Na + HO-CH₂-SO₂Na

Molecular weight of Na₂S₂O₄=174.1071 g/mol
Molecular weight of CH₂O=30.0260 g/mol
Molecular weight of HO-CH₂-SO₃Na =134.0869 g/mol
Molecular weight of HO-CH₂-SO₂Na =118.0875 g/mol

Then if I dissolve 100 grams Na₂S₂O₄ in water and add 34.4914 grams CH₂O I will get 77.0140 grams HO-CH₂-SO₃Na and 67.8246 grams HO-CH₂-SO₂Na

ChenBeier wrote: ↑Wed Mar 20, 2024 3:37 am You mix equimolar amount of bisulfite powder and formaldehyde. Let it crystallize under a good ventilated hood.

NaHSO₃ + CH₂O => HOCH₂- SO₃ Na

It can be produced also as byproduct from Dithionite

https://en.m.wikipedia.org/wiki/Rongalite

Na₂S₂O₅ + H₂O → 2 Na+ + 2 HSO₃−

Molecular weight of Na₂S₂O₅=190.1065 g/mol
Molecular weight of NaHSO₃=104.0609 g/mol
Molecular weight of CH₂O=30.0260 g/mol

So if I dissolve 100 grams Na₂S₂O₅ in water, I will get 109.4764 grams NaHSO₃

Then I need to add 31.5886 grams formaldehyde to the mixture and I will get 141.065 grams CH₃NaO₄S

Is my calculations right

Correct

ChenBeier wrote: ↑Tue Apr 02, 2024 7:53 amCorrect

Thank you

What about commercial formaldehyde solutions? Just noticed almost every brand have methanol in it as a stabilizer. Is methanol affect this reactions?

No it doesn't effect.

ChenBeier wrote: ↑Tue Apr 02, 2024 11:25 pm No it doesn't effect.

Thank you