Molecular formula of the compound CH₂O
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Molecular formula of the compound CH₂O
Please help me with this question:
Given the empirical formula CH₂O, what is the molecular formula of the compound?
Thanks in advance.
Given the empirical formula CH₂O, what is the molecular formula of the compound?
Thanks in advance.
- ChenBeier
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Re: Molecular formula of the compound CH₂O
Could be everything. Not much Information.
X = 1 its formaldehyde
X = 6 its C6H12O6 one sogar like glucose, fructose, and others
X = 1 its formaldehyde
X = 6 its C6H12O6 one sogar like glucose, fructose, and others
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Re: Molecular formula of the compound CH₂O
For example, if the molar mass of the compound is found to be 30 g/mol, then the molecular formula would be the same as the empirical formula because the molar mass of the compound equals the molar mass of the empirical formula unit:
Molecular formula = Empirical formula = CH2O
If the molar mass is different, we would need to determine how many empirical formula units are present in the molecular formula by dividing the molar mass of the compound by the molar mass of the empirical formula.
Number of empirical units = Molar mass of compound/Molar mass of empirical formula
Molecular formula = Empirical formula = CH2O
If the molar mass is different, we would need to determine how many empirical formula units are present in the molecular formula by dividing the molar mass of the compound by the molar mass of the empirical formula.
Number of empirical units = Molar mass of compound/Molar mass of empirical formula
Re: Molecular formula of the compound CH₂O
If the molar mass is 30 g/mol it is formaldehyde.
C (12)H(1)O(16) 12+2+16=30.
C (12)H(1)O(16) 12+2+16=30.
- ChenBeier
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Re: Molecular formula of the compound CH₂O
But it wasn't
It was 60 g/mol
It was 60 g/mol
Re: Molecular formula of the compound CH₂O
Why? If it is formaldehyde it will be 30g/mol.
- ChenBeier
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Re: Molecular formula of the compound CH₂O
Because the teachers has given it.
Re: Molecular formula of the compound CH₂O
I not understand. Molar mass of formaldehyde is 12+1+1+16 = 30 g/mol? Where is the magic?
- ChenBeier
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Re: Molecular formula of the compound CH₂O
The empieric formula is 30 g/mol, but the measured molar mass was 60 g/l.
It could be also 180 g/mol if it is a sugar C6H12O6 means 6 x CH2O.
Empieric formula says nothing about the real molecule. Only with 30 g/mol it could be formaldehyde.
It could be also 180 g/mol if it is a sugar C6H12O6 means 6 x CH2O.
Empieric formula says nothing about the real molecule. Only with 30 g/mol it could be formaldehyde.
Re: Molecular formula of the compound CH₂O
If molar mass is 60 g/mol it may be something like this: OH-CH=CH-OH. But i not found this substance in the internet. I search for acetyleneglicol i found that acetyleneglicol is exist but i didn't found it's formula.
Last edited by Nimmull on Mon Mar 18, 2024 9:51 pm, edited 1 time in total.
Re: Molecular formula of the compound CH₂O
Also it may by aldehyde: OH-CH2-CO-H but i really not found what substance is.
- ChenBeier
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Re: Molecular formula of the compound CH₂O
Possibilities CH3COOH, acetic acid, HCOOCH3 Methylformiate, HOCH2CHO Glycolaldehyde,
Re: Molecular formula of the compound CH₂O
Oh! I forget acetic acid! This substance is (CH2O)*2.
Re: Molecular formula of the compound CH₂O
If it was scool task then acetic acid as more simple substance.
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Re: Molecular formula of the compound CH₂O
To find the molecular formula from the empirical formula, you need to know the molar mass of the compound. The empirical formula CH₂O has the following molar masses:
Carbon (C): 12.01 g/mol
Hydrogen (H): 1.01 g/mol
Oxygen (O): 16.00 g/mol
So, the total molar mass of CH₂O is:
(12.01 g/mol) + 2*(1.01 g/mol) + 16.00 g/mol = 30.03 g/mol
Now, you need to compare the molar mass of the empirical formula to the molar mass of the compound to determine the ratio between them.
Let's assume the molar mass of the compound is 60.06 g/mol (just for example).
The ratio between the molar mass of the compound and the empirical formula is:
(60.06 g/mol) / (30.03 g/mol) = 2
So, the molecular formula will have twice the number of atoms as the empirical formula. Therefore, the molecular formula of the compound is:
C₂H₄O₂
Carbon (C): 12.01 g/mol
Hydrogen (H): 1.01 g/mol
Oxygen (O): 16.00 g/mol
So, the total molar mass of CH₂O is:
(12.01 g/mol) + 2*(1.01 g/mol) + 16.00 g/mol = 30.03 g/mol
Now, you need to compare the molar mass of the empirical formula to the molar mass of the compound to determine the ratio between them.
Let's assume the molar mass of the compound is 60.06 g/mol (just for example).
The ratio between the molar mass of the compound and the empirical formula is:
(60.06 g/mol) / (30.03 g/mol) = 2
So, the molecular formula will have twice the number of atoms as the empirical formula. Therefore, the molecular formula of the compound is:
C₂H₄O₂