Complex electrolysis question

[bohojekek]

The question in regard to the attached image below is:
Explain why the carbon electrode cannot be replaced with an iron electrode.

The answer states that iron is a STRONGER REDUCING AGENT than fluorine and would be preferentially oxidised.

Iron’s standard potential for oxidation is +0.44 V. Fluorine’s standard potential for oxidation is -2.89 V.

This is my thought process: the stronger the reducing agent, the more likely the substance is to oxidise. The more likely a substance is to oxidise, the lower its standard electrode potential. So how is iron the stronger reducing agent if fluorine’s standard reduction potential is lower? Am I not meant to flip the signs when determining what reduces and oxidises even for species I know are oxidising?

[ChenBeier]

It is opposit

Iron’s standard potential for oxidation is +0.44 V. Fluorine’s standard potential for oxidation is -2.89 V.

Fe => Fe₂+ + 2e- -0,44 V
2 F- => F₂ + 2 e- +2,85 V
Iron has the lower redox potential.

Also Carbon will be attacked by flourine. Beside F₂ also CF₄ will be developed.