Chemistry Forum

I am just getting into chemistry and I am having a hard time balancing equations correctly.

Water is reactant for the oxidation part, it is product for the reducing part in acidic environment.
So start with redox pair. Here ClO₃- / ClO₂ and SbO+/Sb₂O₅

REDUCTION
ClO₃- + 2 H+ => ClO₂ + H₂O
Balancing charges with e-
ClO₃- + 2 H+ + e- => ClO₂ + H₂O

OXIDATION
2 SbO+ + 3 H₂O => Sb₂O₅ + 6 H+
Balancing charges with e-
2 SbO+ + 3 H₂O => Sb₂O₅ + 6 H+ + 4 e-

Multiplikation of first equation by 4 to get the same amount of electrons.

4 ClO₃- + 8 H+ + 4 e- => 4 ClO₂ + 4H₂O

Addition and Balance electron H+ and water

4 ClO₃- + 2 H+ + 2 SbO+ => 4 ClO₂ + Sb₂O₅ + H₂O

In sum water is product.

Finished