Chemistry Forum

MnCl₂+2NH₄VO₃. i need to get MnV₂O₆

MnCl₂ + 2 NH₄VO₃ => MnV₂O₆ + 2 NH₄Cl
NH₄Cl => NH₃ + HCl vapour

To obtain MnV₂O₆ from MnCl₂ and NH₄VO₃, you would need to perform a redox reaction and adjust the stoichiometry accordingly. Here's the balanced chemical equation:

3 MnCl₂ + 5 NH₄VO₃ + 9 H₂O → MnV₂O₆ + 10 NH₄Cl + 6 HCl

In this reaction, 3 moles of MnCl₂ react with 5 moles of NH₄VO₃ to yield 1 mole of MnV₂O₆, along with the formation of 10 moles of NH₄Cl and 6 moles of HCl. It's important to note that this is a balanced equation, meaning that the number of atoms of each element is the same on both sides.

Please exercise caution when working with chemicals and follow appropriate safety measures.

To much nonsense

Your equation isn't balanced and its also no redox reaction.

Which Atom is oxidised and which is reduced? No one

Also 3 MnCl₂ gives MnV₂O₆, what happens to the other 2 Mn

To obtain MnV₂O₆ from MnCl₂ and NH₄VO₃, you can follow the following steps:

Start by preparing a solution of MnCl₂ by dissolving the compound in water.
Similarly, prepare a solution of NH₄VO₃ by dissolving it in water.
Mix the two solutions together slowly while stirring.
A reaction will occur, resulting in the formation of a precipitate.
Filter the precipitate and wash it with distilled water to remove any impurities.
Dry the obtained solid thoroughly.
The resulting solid is MnV₂O₆, a compound containing manganese in its +5 oxidation state.
Please note that handling chemicals should be done with caution and proper safety measures a small world cup

The resulting solid is MnV₂O₆, a compound containing manganese in its +5 oxidation state

No

I think you mean vanadium. Manganese is still Mn 2+