This topic is about molality
How many grams of NaHCO3 are needed to prepare a 2 molar solution with 200 mL of water?
Can someone help me, Thanks.!!!
Molality Question
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- ChenBeier
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Re: Molality Question
Do you want molality or molarity. Both are different.
Molarity is concentration in mass/volume like g/l. Molality is mass/(mass of solution). Like g/kg.
For molarity you need molar mass of NaHCO3 what is 84 g/mol.
A 2 M solution contain 2 mol/l. So you have to dissolve 168 g and fill up with water to 1 l, for 200 ml you need 33,6 g.
For a 2 molal solution you take a balance put in a beaker glass 168 g NaHCO3 and add water to 1 kg , what should be 832 g H2O. For 200 g you need 33,6 g NaHCO3 and 166,4 g H2O.
But both is not possible, because solubility is max. 93,4 g/l what means 1,11 mol
Molarity is concentration in mass/volume like g/l. Molality is mass/(mass of solution). Like g/kg.
For molarity you need molar mass of NaHCO3 what is 84 g/mol.
A 2 M solution contain 2 mol/l. So you have to dissolve 168 g and fill up with water to 1 l, for 200 ml you need 33,6 g.
For a 2 molal solution you take a balance put in a beaker glass 168 g NaHCO3 and add water to 1 kg , what should be 832 g H2O. For 200 g you need 33,6 g NaHCO3 and 166,4 g H2O.
But both is not possible, because solubility is max. 93,4 g/l what means 1,11 mol
Re: Molality Question
its about molality, thanks for answer, is a question for my class, but I don't understand, because I resolve it, and tha answer was 252 g, buy I'm not sure
- ChenBeier
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Re: Molality Question
252 g is definitive wrong. How do you calculate.
Re: Molality Question
Yes, you right,
I solved it again and I used this method:
molality Solute = m(molality) * molar weight * Kg
mste: 3 * 84 * 0.2 ( 200 ml to kilogram) = 50.4
i think, that this is the answer
I solved it again and I used this method:
molality Solute = m(molality) * molar weight * Kg
mste: 3 * 84 * 0.2 ( 200 ml to kilogram) = 50.4
i think, that this is the answer
- ChenBeier
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- Joined: Wed Sep 27, 2017 7:25 am
- Location: Berlin, Germany
Re: Molality Question
No, the answer I had given above 33,6 g NaHCO3 and 166,4 g H2O to make 200g, not 200 ml.For calculation you need also specific gravity of the solution.
200 ml is not 200 g.
3? * 84 / g/mol * 0,2 l = 50,4 ?* g/mol * l
The unit must be g/kg
200 ml is not 200 g.
Where does the 3 comes from ? Check also the unit.3 * 84 * 0.2 ( 200 ml to kilogram) = 50.4
3? * 84 / g/mol * 0,2 l = 50,4 ?* g/mol * l
The unit must be g/kg