Chemistry Forum

Al₂Si₂O₇ + CaCO₃ + SiO₂ = Al₆Si₂O₁₃ + CaSiO₃ + CaAl₄O₇
Al₂Si₂O₇ + CaCO₃ + SiO₂ = ?
Al₂Si₂O₇ + CaCO₃ = ?
Al₂Si₂O₇ + SiO₂ = ?

Reaction of metakaolin with carbonate and silicon dioxide during sintering = mullite, wollastonite and grossite

The answer:
3Al₂O₃.2SiO₂ + CaCO₃ + SiO₂ = Al₆Si₂O₁₃ + CaSiO₃ + CO₂
5Al₂O₃.2SiO₂ + CaCO₃ = Al₆Si₂O₁₃ + CaAl₄O₇ + CO₂

The reactions you described include the formation of new compounds through the combining of existing ones. For every reaction, these balanced chemical equations apply:

1. Al₂Si₂O₇ + CaCO₃ + SiO₂ = Al₆Si₂O₁₃ + CaSiO₃ + CaAl₄O₇

2. Al₂Si₂O₇ + CaCO₃ = Al₆Si₂O₁₃ + CaSiO₃

3. Al₂Si₂O₇ + SiO₂ = Al₆Si₂O₁₃

Please help me with
CH₃CH₂OH + K₂Cr₂O₇ + H₂SO₄ → CH₃COOH + Cr₂(SO₄)₃ + K₂SO₄ + H₂O

Oxidation CH₃CH₂OH + H₂O => CH₃CHO + 4 H+ + 4 e-
Reduction Cr₂O₇ 2- + 14 H+ + 6 e- => 2 Cr 3+ + 7 H₂O

Continue yourself

Al₂Si₂O₇ + CaCO₃ = ?
This reaction likely forms some combination of the compounds mullite, wollastonite, and grossite. However, the exact products formed would depend on the specific conditions of the reaction, such as temperature,incredibox pressure, and the presence of any catalysts.

Al₂Si₂O₇ + SiO₂ = ?
This reaction may also produce some combination of mullite, depending on the specific conditions. Again, the exact products formed would depend on the reaction conditions.

The formula is really diverse with your answers. I like the website because there are many chemical equations I can balance and solve.

great

The correct answer is:
Al₂Si₂O₇ + CaCO₃ + SiO₂ → Al₆Si₂O₁₃ + CaSiO₃ + CaAl₄O₇
Produces mullite, wollastonite and grossite during calcination.

It's not balanced.

Al₂Si₂O₇ + CaCO₃ + SiO₂ → Al₆Si₂O₁₃ + CaSiO₃ + CaAl₄O₇

Left 2 Al right 10 Al
Left 1 Ca right 2 Ca
Left 12 O right 23 O

The result was already given, don't post nonsense equations.

oh solar smash, So the answer I gave is wrong. Thanks for reminding me and letting me know the correct answer.

5 Al₂Si₂O₇ + 10 CaCO₃+ SiO₂→ Al₆Si₂O₁₃ + 9 CaSiO₃ + CaAl₄O₇ + 10 CO₂
Balanced equation.

Thanks,