NdBa2Cu3O7

[superfr]

hi
i have prepared YBa₂Cu₃O₇ in lab using following info
formula mass ratio actual mass mixed
Y₂O₃ 11.29 0.8954
BaCO₃ 39.47 3.1300
CuO 23.86 1.8925

now i wanna make NdBa₂Cu₃O₇ what will be the exact masses mixed i just cant get it. plz help.
mol wt:
Y 88.9 Ba 137 Cu 64 O 16 Nd 144.242 Y₂O₃ 225.81
BaCO₃ 197.3368 CuO 79.54 Nd₂O₃ 336.484

[Vitalii]

hi
i have prepared YBa₂Cu₃O₇ in lab using following info
formula mass ratio actual mass mixed
Y₂O₃ 11.29 0.8954
BaCO₃ 39.47 3.1300
CuO 23.86 1.8925

now i wanna make NdBa₂Cu₃O₇ what will be the exact masses mixed i just cant get it. plz help.
mol wt:
Y 88.9 Ba 137 Cu 64 O 16 Nd 144.242 Y₂O₃ 225.81
BaCO₃ 197.3368 CuO 79.54 Nd₂O₃ 336.484

Calculate masses of Nd₂O₃, BaCO₃ and CuO which are necessary to prepare 1 mole of NdBa₂Cu₃O₇:
m(Nd₂O₃) = 336.484/2
m(CuO) = 3 * 79.54
m(BaCO₃) = 2 * 197.3368
if you need to prepare smaller amount of NdBa₂Cu₃O₇, just scale down all the masses (divide them by the same number).