Chemistry Forum

The alkaloid strychnine, a compound containing carbon, hydrogen, nitrogen and oxygen was submitted for elemental analysis. Combustion of a 0.3432-g sample in oxygen gave 0.2032-g H₂O and 0.9483-g CO₂.
A 0.4932-g sample yielded 36.5 ml of nitrogen gas with a density of 1.13 g/L. The molecular weight of the compound was found to be 334.

Calculate (a) the percentage composition

(b) the empirical formula

(c) the molecular formula

Any chemistry help will be accepted. I am working on this question.

For a) calculate the amount H and C from the given masses either in mol and g and the percentage.
From the second Experiment also calculate the amount of nitrogen N .
b) 100 - the summery of C H N gives the amount of Oxygen O.
c) From the given molar mass and the calculated empiric formula the composition can be calculated.

a) Percentage composition of the compound:
Carbon:75.41%
Nitrogen:8.36%
Hydrogen:6.62%
Oxygen:9.61%

b) C₂₁H₂₂N₂O₂
c)C₂₁H₂₂N₂O₂

Calculation path is missing.