Balance equations
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Balance equations
balance
Last edited by studygives on Tue Jun 02, 2020 11:05 am, edited 1 time in total.
- ChenBeier
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1. Build Redox pair CrCl3 /Na2CrO4 and H2O2/ OH-
2. Ions Cr3+/ CrO4 2- and H2O2/ OH-
3. Alkaline condition OH-
4. Cr3+ + 8 OH- => CrO4 2- + 4 H2O
5. Balance Electron
Cr3+ + 8 OH- => CrO4 2- + 4 H2O + 3 e-
H2O2 + 2 e-=> 2 OH-
Kgv = 6 for Elektrons
2 Cr3+ 16 OH-=> 2 CrO4 2- + 8 H2O + 6 e-
3 H2O2 + 6 e- => 6 OH-
Addition
2 Cr3+ 10 OH- + 3 H2O2 => 2 CrO4 2- + 8 H2O
Adding Na+ + Cl-
2 CrCl3+ 10 NaOH+ 3 H2O2 => 2 Na2CrO4 + 8 H2O + 6 NaCl
Finished
2. Ions Cr3+/ CrO4 2- and H2O2/ OH-
3. Alkaline condition OH-
4. Cr3+ + 8 OH- => CrO4 2- + 4 H2O
5. Balance Electron
Cr3+ + 8 OH- => CrO4 2- + 4 H2O + 3 e-
H2O2 + 2 e-=> 2 OH-
Kgv = 6 for Elektrons
2 Cr3+ 16 OH-=> 2 CrO4 2- + 8 H2O + 6 e-
3 H2O2 + 6 e- => 6 OH-
Addition
2 Cr3+ 10 OH- + 3 H2O2 => 2 CrO4 2- + 8 H2O
Adding Na+ + Cl-
2 CrCl3+ 10 NaOH+ 3 H2O2 => 2 Na2CrO4 + 8 H2O + 6 NaCl
Finished
Last edited by ChenBeier on Mon Jun 01, 2020 1:46 pm, edited 2 times in total.
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- ChenBeier
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What do you don't understand? You have to pick the oxidation and Reduction Compounds on both side of the equation.
According it is alkaline ( NaOH) you add OH- on edukt side and get water on product side
Balance and add electrons for the balanced charge,
Then for both equation you get the electrons equal .
Then Addition of both equation, electrons and some water will be eliminated.
At the end you add the spectator ions sodium and chloride.
According it is alkaline ( NaOH) you add OH- on edukt side and get water on product side
Balance and add electrons for the balanced charge,
Then for both equation you get the electrons equal .
Then Addition of both equation, electrons and some water will be eliminated.
At the end you add the spectator ions sodium and chloride.