Hello,
in my country its not possible to buy Sodium lactate or it is crazy expensive.
Seller of chemicals for my soap making told that i could make Sodium lactate at home from lactic acid (C3H6O3) and sodium carbonate (Na2CO3).
His advice was just put sodium carbonate into lactic acid. When sodium carbonate is no longer dissolves in lactic acid - i will get Sodium lactate.
I've got 80% lactic acid and 99.6% sodium carbonate from him. But really would like to know more precise measurements.
Could anyone please help to calculate how many grams of sodium carbonate (99.6%) i need to put into 1000g of lactic acid (80%)?
What would be a concentration of Sodium lactate at given solution?
Thank you very much in advance for help!
Making of Sodium lactate at home
Moderators: Xen, expert, ChenBeier
- ChenBeier
- Distinguished Member
- Posts: 1565
- Joined: Wed Sep 27, 2017 7:25 am
- Location: Berlin, Germany
1000g 80% means 800g 100%. Molare mass of lactid acid is 90 g/mol
This gives n = m/M => 800g/90g = 8,89 mol
According Na2CO3 + 2 CH3CH(OH)COOH => 2 CH3CH(OH) COONa + H2O + CO2
the half 4,44 mol of sodium carbonate is needed. The molar mass is 106 g/mol
This gives 471 g 100% or 473g 99,6% sodium carbonate.
The amount of sodium lactate will be 995 g.
This gives n = m/M => 800g/90g = 8,89 mol
According Na2CO3 + 2 CH3CH(OH)COOH => 2 CH3CH(OH) COONa + H2O + CO2
the half 4,44 mol of sodium carbonate is needed. The molar mass is 106 g/mol
This gives 471 g 100% or 473g 99,6% sodium carbonate.
The amount of sodium lactate will be 995 g.
Last edited by ChenBeier on Thu Feb 13, 2020 1:00 am, edited 1 time in total.