Redox
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H
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Joined: 14 Nov 2019
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Redox


I need some help, how do I ajust this ecuation with redox method?

H2S + NaCr2O7 + H2SO4 = Cr2(SO4)3 + NaHSO4 + S + H2O


Thanks.
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H
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By the way, I already tried to use the app of here to ajust It, but It says "There's infinite ways to solve It" so im confused.
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ChenBeier
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Separate to redox parts

H2S/ S and Cr2O7 2- / Cr3+

Oxidation: H2S => 2 H+ + 2 e- + S

Reduction: Cr2O7 2- + 14 H+ + 6 e- => 2 Cr3+ + 7 H2O

Balance electrons
3 H2S => 6 H+ + 6 e- + 3 S

Addition

Cr2O7 2- + 3 H2S + 8 H+ => 2 Cr3+ + 3 S + 7 H2O

Add of Na+ and SO4 2-


Na2Cr2O7 + 3 H2S + 4 H2SO4 => Cr2(SO4)3 + 3 S + Na2SO4 + 7 H2O
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