Help please
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Help please
I am not sure if I have solved this correctly.
Sb (OH)3 +Na2S --- SbS3
I have attempted to check my answer, but I can't find it online.
Thank you!!!!!
Sb (OH)3 +Na2S --- SbS3
I have attempted to check my answer, but I can't find it online.
Thank you!!!!!
-
- Newbie
- Posts: 4
- Joined: Sun Sep 09, 2018 8:48 am
Thank you
The lab required Sb3+
Sb OH3 + Na2 S-----2SbS3 +2Na OH3
I have a problem grasping is it the total number of charges that need to be equal on both sides?
Sb OH3 + Na2 S-----2SbS3 +2Na OH3
I have a problem grasping is it the total number of charges that need to be equal on both sides?
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- Newbie
- Posts: 4
- Joined: Sun Sep 09, 2018 8:48 am
Think I got it!
I think I have it LOL
SbOH3 + Na2S-----Sb + NaOH
SbOH3 + Na2S-----Sb + NaOH
- ChenBeier
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No
In Sb3+ + S2- , we have 3+ and 2- . Like in mathematics 1/3 and 1/2 you have to go 6.
2 * 3+ = -(3* 2-)
2 Sb3+ + 3 S2- => Sb2S3
With your compounds it means
2 Sb(OH)3 + 3 Na2S => Sb2S3 + 6 NaOH
In Sb3+ + S2- , we have 3+ and 2- . Like in mathematics 1/3 and 1/2 you have to go 6.
2 * 3+ = -(3* 2-)
2 Sb3+ + 3 S2- => Sb2S3
With your compounds it means
2 Sb(OH)3 + 3 Na2S => Sb2S3 + 6 NaOH
Last edited by ChenBeier on Sun Sep 09, 2018 12:23 pm, edited 1 time in total.
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Thank you
Thank you for your help. I see how you solved it and I will practice more.
Thank you for your help!
Thank you for your help!
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Re: Help please
reddnwaiting wrote:I am not sure if I have solved this correctly.
Sb (OH)3 +Na2S --- SbS3
I have attempted to check my answer, but I can't find it online.
Thank you!!!!!
2Sb(OH)3(s)+3NA2S(ac)=SB2S3(s)+6NaOH(ac)
-Sb has +3
-S has -2
-Na has+1
-OH has -1