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Help Please!
Posted: Tue Aug 07, 2018 9:54 am
by gatorgirl1
In the lab you have decided to mix together aqueous solutions of lead (IV) nitrate and potassium carbonate. Instead of calculating how much of each of each solution that you need, you decide to just combine equal volumes of each solution. If you combine 43.9 mL of 0.592 M lead (IV) nitrate solution with 43.9 mL of 0.164 M potassium carbonate solution, what mass (in g) of precipitate would you expect to produce?
Posted: Wed Aug 08, 2018 3:29 am
by ChenBeier
The first thing is, that lead-IV- don't exist as nitate either as carbonate. Lead-IV is only known as Oxide, Flouride, Chloride, Hexachlorplumbate and the organic compounds like Tetraethyllead used in fuel as anti knocking compound.
Maybe check first that you have Lead(II)nitrate.
to solve the exercise:
1. chemical equation
2. calculate the mole of lead
3. calculate the mole of Carbonate
4. check how much moles of lead carbonate will be formed
5. convert this to the mass