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CuSCN + KIO3 + HCl = CuSO4 + KCl + HCN + ICl + H2O
Posted: Sat Jun 16, 2018 1:44 pm
by Neon
How do I edit this chemical equation? I ask for the procedure.
CuSCN + KIO
3 + HCl = CuSO
4 + KCl + HCN + ICl + H
2O
Thank you in advance!
Posted: Sun Jun 17, 2018 1:37 am
by ChenBeier
First you have to check what will be oxidiesed and what will be reduced.
Oxidiesed Cu+ => Cu 2+
SCN- => SO42- + CN-
Redused: IO3- => I+ !! later ICl will beformed
Develop for this the half reaction.
Posted: Tue Jun 19, 2018 12:25 am
by ChenBeier
As present here is the solution
Code: Select all
4 CuSCN +7 KIO3 + 14 HCl => 4 CuSO4 + 7 KCl + 4 HCN + 7 ICl + 5 H2O