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How balance chemical equation
Posted: Sat Apr 14, 2018 12:42 pm
by Zbych
Hello
?KNO3+?C12H22O11=?K2O+?N2+?H2O+50% CO+50% CO2
Posted: Tue Apr 17, 2018 6:31 am
by ChenBeier
Code: Select all
36 KNO3 + 5 C12H22O11 => 18 K2O + 18 N2 + 55 H2O + 30 CO2 + 30 CO
How balance chemical equation
Posted: Wed Apr 18, 2018 12:55 am
by Zbych
ChenBeier wrote:Code: Select all
36 KNO3 + 5 C12H22O11 => 18 K2O + 18 N2 + 55 H2O + 30 CO2 + 30 CO
Hi Chen. How did you do that? Manually.
Regards Zbych
Posted: Wed Apr 18, 2018 1:11 am
by ChenBeier
You have to develop the oxidation and reduction equation first.
sugar you can change to
Then you take each 6 C to oxidize to
and CO
The reduction is
Code: Select all
2 KNO3 => N2 + K2O + 5 (O)
The combination guides to the result.
Posted: Wed Apr 18, 2018 10:54 pm
by Zbych
Hi Chen
Thank you for your comprehensive answer
Greetings Zbych