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Possible products of the equation

Posted: Tue Jan 16, 2018 10:52 pm
by ammusvijay
KOH+KMnO4+Ca(NO3)2.4H2O+H2O+MnCl2=

Posted: Wed Jan 17, 2018 12:42 am
by phongphanp
Depend on probability ! Read detail on good Chemistry table .

Re: Possible products of the equation

Posted: Wed Jan 17, 2018 5:03 am
by ChenBeier
ammusvijay wrote:KOH+KMnO4+Ca(NO3)2.4H2O+H2O+MnCl2=

This will guide to disproportion

MnO4- + 2 H2O + 3 e- => MnO2 + 4 OH-


Mn2+ + 4 OH- = > MnO2 + 2 H2O + 2 e-

All others are spectator ions.