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Possible products of the equation
Posted: Tue Jan 16, 2018 10:52 pm
by ammusvijay
KOH+KMnO4+Ca(NO3)2.4H2O+H2O+MnCl2=
Posted: Wed Jan 17, 2018 12:42 am
by phongphanp
Depend on probability ! Read detail on good Chemistry table .
Re: Possible products of the equation
Posted: Wed Jan 17, 2018 5:03 am
by ChenBeier
ammusvijay wrote:KOH+KMnO4+Ca(NO3)2.4H2O+H2O+MnCl2=
This will guide to disproportion
MnO
4- + 2 H
2O + 3 e- => MnO
2 + 4 OH-
Mn
2+ + 4 OH- = > MnO
2 + 2 H
2O + 2 e-
All others are spectator ions.