Cu + Fe(NO3)3 = ???
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L34
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Cu + Fe(NO3)3 = ???


Cu + Fe(NO3)3 = ???
electronic balance method. Help me! The reaction should go so that Fe changes its oxidation state from +3 to +2
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ChenBeier
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Its simple.

Fe3+ + e- => Fe2+

Cu => Cu2+ +2 e-

KGV is 2

2 Fe3+ + 2 e- => 2 Fe2+


Addition and eliminierung of electrons

2 Fe3+ + Cu => 2 Fe2+ + Cu2+

The Nitrat is normaly spectactor ion.

Depending on pH it can also oxidies Cu and Fe2+

and will be reduced to NO.

NO3- + 4 H+ + 3 e- => NO + 2 H2O
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phongphanp
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Last equation is not clear such as electron , H from ?
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ChenBeier
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What is not clear. An iron-III solution is acidic in pH. So in small amount you will have HNO3, and this also will attack copper.

Fe3+ + H2O => FeOH2+ + H+
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