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How can I balance this reaction?
Posted: Thu Jan 04, 2018 4:10 am
by maraiannotta
MnO4- = MnO4{---} + O2
Thank you![/code]
Posted: Thu Jan 04, 2018 11:55 am
by ChenBeier
MnO4- + 2 e- => MnO4 3- Reduction
4 OH- => 2 H2O + O2 + 4 e- Oxidation
Scm = 4
2 MnO4- + 4 e- => 2 MnO4 3-
Addition
2 MnO4- + 4 OH- => 2 MnO4 3- + 2 H2O + O2
finished
Posted: Thu Jan 04, 2018 1:59 pm
by maraiannotta
ChenBeier wrote:MnO4- + 2 e- => MnO4 3- Reduction
4 OH- => 2 H2O + O2 + 4 e- Oxidation
Scm = 4
2 MnO4- + 4 e- => 2 MnO4 3-
Addition
2 MnO4- + 4 OH- => 2 MnO4 3- + 2 H2O + O2
finished
Thank you so much!
Posted: Thu Jan 04, 2018 11:11 pm
by alvintopo
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