URGENT CuSO4*5H2O + (NH4)2S2O8?????
Posted: Tue Dec 05, 2017 1:21 am
I can't seem to figure out a reaction for CuSO4*5H2O + (NH4)2S2O8 in the presence of pyridine to make [Cu(py)4]S2O8. Where should the waters go? Should the SO4 join with the ammonium?
Same as for AgNO3 and (NH4)2S2O8 in the presence of pyridine to make [Ag(py)4]S2O8.
Please, please, pleaaase help me out if you're up. I'll probably be up for another 3-4 hours.
Same as for AgNO3 and (NH4)2S2O8 in the presence of pyridine to make [Ag(py)4]S2O8.
Please, please, pleaaase help me out if you're up. I'll probably be up for another 3-4 hours.