Chemistry Forum

I need help with this problem.

A certain rocket uses butane, C₄H₁₀, as fuel. How many kilograms of liquid oxygen should be carried for the complete combustion of each 1.00 kg of butane to carbon dioxide and water vapor?

What I have so far:

2C₄H₁₀ + 13O₂ = 8CO₂ + 10H₂O <-- Balanced Equation
1 mole C₄H₁₀ = 58g
1 mole O₂ = 32g

Hi! It's very easy to solve. You only have to do this divition: 416kg of O₂/116 kg of C₄H₁₀ = 3.586kg of O₂