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Di Mezza Alfredo
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Joined: 05 Jan 2017
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PostPosted: Thu Jan 05, 2017 7:47 am    Post subject: Can someone explain me how to balance this reaction? Reply with quoteFind all posts by Di Mezza Alfredo

(Ru++) +(NH4+) + (Br2) = (Br-) +Ru(NO2)2
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bejoy
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PostPosted: Tue Jan 10, 2017 3:02 am    Post subject: can we know the source for this reaction Reply with quoteFind all posts by bejoy

can we know the source for this reaction
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GrahamKemp
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PostPosted: Wed Apr 19, 2017 7:09 pm    Post subject: Re: Can someone explain me how to balance this reaction? Reply with quoteFind all posts by GrahamKemp

Di Mezza Alfredo wrote:
(Ru++) +(NH4+) + (Br2) = (Br-) +Ru(NO2)2


Todo, balance:
  • Ru{2+} + NH4{+} + Br2 = Br{-} + Ru(NO2)2

Remove the spectator ion Ru{2+} and divide into Red/Ox half cells.
  • 2 NH4{+} = 2 NO2{-}
  • Br2 = 2 Br{-}

Balance O with water
  • 2 NH4{+} + 4 H2O = 2 NO2{-}
  • Br2 = 2 Br{-}

Balance H with protons
  • 2 NH4{+} + 4 H2O = 2 NO2{-} + 16 H{+}
  • Br2 = 2 Br{-}

Migrate to basic
  • 2 NH4{+} + 16 OH{-} = 2 NO2{-} + 12 H2O
  • Br2 = 2 Br{-}

Balance charge with electrons
  • 2 NH4{+} + 16 OH{-} = 2 NO2{-} + 12 H2O + 12 e{-}
  • 6 Br2 + 12 e{-} = 12 Br{-}

Recombine:
  • Ru{2+} + 2 NH4{+} + 16 OH{-} + 6 Br2 = Ru(NO2)2 + 12 Br{-} + 12 H2O
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