Chemistry Forum

Di Mezza Alfredo wrote:(Ru++) +(NH₄+) + (Br₂) = (Br-) +Ru(NO₂)₂

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  Ru{2+} + NH4{+} + Br2 = Br{-} + Ru(NO2)2

Ru{2+}

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   2 NH4{+} = 2 NO2{-} 

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   Br2 = 2 Br{-}

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   2 NH4{+} + 4 H2O = 2 NO2{-} 

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   Br2 = 2 Br{-}

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   2 NH4{+} + 4 H2O = 2 NO2{-} + 16 H{+} 

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   Br2 = 2 Br{-}

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   2 NH4{+} + 16 OH{-}  = 2 NO2{-} + 12 H2O 

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   Br2 = 2 Br{-}

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   2 NH4{+} + 16 OH{-}  = 2 NO2{-} + 12 H2O + 12 e{-}

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   6 Br2 + 12 e{-} = 12 Br{-}

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   Ru{2+} + 2 NH4{+} + 16 OH{-} + 6 Br2 = Ru(NO2)2 + 12 Br{-} + 12 H2O

GrahamKemp wrote:

Di Mezza Alfredo wrote:(Ru++) +(NH₄+) + (Br₂) = (Br-) +Ru(NO₂)₂

Todo, balance:

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  Ru{2+} + NH4{+} + Br2 = Br{-} + Ru(NO2)2

Remove the spectator ion

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Ru{2+}

and divide into Red/Ox half cells.

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   2 NH4{+} = 2 NO2{-} 

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   Br2 = 2 Br{-}

Balance O with water

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   2 NH4{+} + 4 H2O = 2 NO2{-} 

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   Br2 = 2 Br{-}

Balance H with protons

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   2 NH4{+} + 4 H2O = 2 NO2{-} + 16 H{+} 

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   Br2 = 2 Br{-}

Migrate to basic

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   2 NH4{+} + 16 OH{-}  = 2 NO2{-} + 12 H2O 

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   Br2 = 2 Br{-}

Balance charge with electrons

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   2 NH4{+} + 16 OH{-}  = 2 NO2{-} + 12 H2O + 12 e{-}

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   6 Br2 + 12 e{-} = 12 Br{-}

Recombine:

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   Ru{2+} + 2 NH4{+} + 16 OH{-} + 6 Br2 = Ru(NO2)2 + 12 Br{-} + 12 H2O