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ctomni231
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PostPosted: Sun Jan 17, 2016 11:20 pm    Post subject: HO2-(aq) + MnO4-(aq) = MnO2(s) + O2(g) Reply with quoteFind all posts by ctomni231

I am completely stumped on how to balance this equation, can I get some advice on how to solve it? Thanks.

HO2-(aq) + MnO4-(aq) = MnO2(s) + O2(g)
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matej789
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PostPosted: Wed Jan 20, 2016 6:10 am    Post subject: Reply with quoteFind all posts by matej789

First it seems the equation might be incomplete seeing as the hydrogen atom specified isnt used, secondly i think you ment ho2 to be H2O2 - hydrogen peroxyde, in that case the equation is as follows:

2-H2O2(aq) + MnO4(aq) = MnO2(s) + 2-O2(g) + 2-H2O(l)
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spadanco
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PostPosted: Mon Aug 21, 2017 5:31 am    Post subject: Reply with quoteFind all posts by spadanco

matej789 wrote:
First it seems the equation might be incomplete seeing as the hydrogen atom specified isnt used, secondly i think you ment ho2 to be H2O2 - hydrogen peroxyde, in that case the equation is as follows:

2-H2O2(aq) + MnO4(aq) = MnO2(s) + 2-O2(g) + 2-H2O(l)

That was interesting
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