basic calculations relating to the mole and stoichiometry
Posted: Sun Feb 01, 2015 6:48 am
The Enzyme carbonic anhydrase catalyses the hydration of CO2.The reaction:
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CO2+H2O=H2CO3,is involved in the transfer of CO2 from the tissues to the lungs via blood stream. One enzyme molecule hydrates 10^6 molecules of CO2 per second. How many Kgs of CO2 are hydrated in hour in one litre by 1*10^(-6) M enzyme?
Answer: 0.1584 kg.
My attempt:-
CO2 + H2O ---> H2CO3
Molecular mass of CO2 = 44 g
No. of moles of enzyme =1*10^(-6) moles
No. of molecules of enzymes present that will hydrate CO2 in one hour = 1*10^(-6)*6.023*10^23 molecules
One molecule of enzyme hydrates No. of molecules of CO2 in one hour = 60*60*10^6 Molecules
So, 1*10^(-6)*6.023*10^23 molecules of enzyme will hydrate = 1*10^(-6)*6.023*10^23 * 60*60*10^6 molecules.
6.023 * 10^23 molecules of CO2 = 44 g
Mass of 3600*6.023*10^23 molecules of CO2 =[44/(6.023*10^23)]*3600*6.023*10^23g =158400 grams of CO2
Thus 158.400 kg of CO2 will be produced.
But my answer comes out to be different from the one given in the standard text book and that's a very standard text book. I've not got any wrong answer till now.
Please guide!
Thanks!! :( :( :(