Chemistry Forum

Posted: **Mon Mar 04, 2013 5:27 pm**

I need to write a balanced chemical equation for the reaction between:

BaCl₂(aq) and KOH(aq)

Please help! Thank You!

Posted: **Mon Mar 04, 2013 5:53 pm**

Where are you having trouble with this?

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First, determine the products. They're obviously going to be Barium hydroxide and Potassium chloride.

Next determine the precipitate. KCl is quite soluble, and a quick check determines that Baryta is not so much.

Code: Select all

_ BaCl2&#40;aq&#41; + _ KOH&#40;aq&#41; = _ Ba&#40;OH&#41;2&#40;s&#41; + _ KCl&#40;aq&#41;

Finally you balance them. Balance the count of Chlorine on both sides, then Hydroxide too.

Balance Cl:

Code: Select all

a BaCl2&#40;aq&#41; + _ KOH&#40;aq&#41; = _ Ba&#40;OH&#41;2&#40;s&#41; + 2a KCl&#40;aq&#41;

Balance OH:

Code: Select all

a BaCl2&#40;aq&#41; + 2b KOH&#40;aq&#41; = b Ba&#40;OH&#41;2&#40;s&#41; + 2a KCl&#40;aq&#41;

Balance Ba, K determines that a=b. For a least integer solution, a=1.
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Code: Select all

 BaCl2&#40;aq&#41; + 2 KOH&#40;aq&#41; =  Ba&#40;OH&#41;2&#40;s&#41; + 2 KCl&#40;aq&#41;

Posted: **Mon Mar 04, 2013 9:10 pm**

Thank you for your help. I was having trouble balancing the two. I think I was making it more difficult than it really was.

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