Precipitation Reaction

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tatumpg79
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Joined: Mon Mar 04, 2013 5:20 pm

Precipitation Reaction

Post by tatumpg79 »

I need to write a balanced chemical equation for the reaction between:

BaCl2(aq) and KOH(aq)

Please help! Thank You!
GrahamKemp
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Joined: Mon Mar 19, 2012 10:12 pm

Re: Precipitation Reaction

Post by GrahamKemp »

Where are you having trouble with this?

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First, determine the products. They're obviously going to be Barium hydroxide and Potassium chloride.

Next determine the precipitate. KCl is quite soluble, and a quick check determines that Baryta is not so much.

Code: Select all

_ BaCl2(aq) + _ KOH(aq) = _ Ba(OH)2(s) + _ KCl(aq)
Finally you balance them. Balance the count of Chlorine on both sides, then Hydroxide too.

Balance Cl:

Code: Select all

a BaCl2(aq) + _ KOH(aq) = _ Ba(OH)2(s) + 2a KCl(aq)
Balance OH:

Code: Select all

a BaCl2(aq) + 2b KOH(aq) = b Ba(OH)2(s) + 2a KCl(aq)
Balance Ba, K determines that a=b. For a least integer solution, a=1.
============================================

Code: Select all

 BaCl2(aq) + 2 KOH(aq) =  Ba(OH)2(s) + 2 KCl(aq)
tatumpg79
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Posts: 2
Joined: Mon Mar 04, 2013 5:20 pm

Post by tatumpg79 »

Thank you for your help. I was having trouble balancing the two. I think I was making it more difficult than it really was.
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