I need to write a balanced chemical equation for the reaction between:
BaCl2(aq) and KOH(aq)
Please help! Thank You!
Precipitation Reaction
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Re: Precipitation Reaction
Where are you having trouble with this?
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First, determine the products. They're obviously going to be Barium hydroxide and Potassium chloride.
Next determine the precipitate. KCl is quite soluble, and a quick check determines that Baryta is not so much.
Finally you balance them. Balance the count of Chlorine on both sides, then Hydroxide too.
Balance Cl:
Balance OH:
Balance Ba, K determines that a=b. For a least integer solution, a=1.
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First, determine the products. They're obviously going to be Barium hydroxide and Potassium chloride.
Next determine the precipitate. KCl is quite soluble, and a quick check determines that Baryta is not so much.
Code: Select all
_ BaCl2(aq) + _ KOH(aq) = _ Ba(OH)2(s) + _ KCl(aq)
Balance Cl:
Code: Select all
a BaCl2(aq) + _ KOH(aq) = _ Ba(OH)2(s) + 2a KCl(aq)
Code: Select all
a BaCl2(aq) + 2b KOH(aq) = b Ba(OH)2(s) + 2a KCl(aq)
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Code: Select all
BaCl2(aq) + 2 KOH(aq) = Ba(OH)2(s) + 2 KCl(aq)