Chemistry Forum

how to find out the equivalent weight of an element which takes part in a disproportion reaction i.e it undergoes both oxidation and reduction.


for example , there's one reaction in which Cl₂---> Cl+3 + Cl-1
for this reaction
1. the equivalent weight = (molar mass of chlorine)/3 + (molar mass of chlorine)/1


OR


2. equivalent weight od cholrine = 1/2 [(molar mass of chlorine)/3 +

(molar mass)/1 ]

(if halved the value of equation 1. to get equation 2. as there are 2 chlorine atoms in a chlorine molecule. is this correct ??).
















(i halved the value

bodwiser wrote:how to find out the equivalent weight of an element which takes part in a disproportion reaction i.e it undergoes both oxidation and reduction.

There will be two equivalent weights: one for oxidation and another for reduction. To calculate equivalent weight you simply divide molar mass of the element by the number of electrons it acquires/looses.