how to find out the equivalent weight of an element which takes part in a disproportion reaction i.e it undergoes both oxidation and reduction.
for example , there's one reaction in which Cl2---> Cl+3 + Cl-1
for this reaction
1. the equivalent weight = (molar mass of chlorine)/3 + (molar mass of chlorine)/1
OR
2. equivalent weight od cholrine = 1/2 [(molar mass of chlorine)/3 +
(molar mass)/1 ]
(if halved the value of equation 1. to get equation 2. as there are 2 chlorine atoms in a chlorine molecule. is this correct ??).
(i halved the value
equivalent weight problem
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equivalent weight problem
Last edited by bodwiser on Tue Jan 30, 2007 3:23 am, edited 1 time in total.
Re: equivalent weight problem
There will be two equivalent weights: one for oxidation and another for reduction. To calculate equivalent weight you simply divide molar mass of the element by the number of electrons it acquires/looses.bodwiser wrote:how to find out the equivalent weight of an element which takes part in a disproportion reaction i.e it undergoes both oxidation and reduction.
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