Unbalanced reaction problem.

[Schrec42]

My problem is :
How many grams of CO₂ would be formed from 20 grams of C₆H₆ in the following (UNBALANCED) reaction? C₆H₆ +O₂ = CO₂ + H₂O . Can anyone help with this please.


Thanks
Schrec

[sharan]

2 C₆H₆ + 15 O₂ = 12 CO₂ + 6 H₂O

umm this is the balanced equation so it is clear that 2 moles of C₆H₆ gives 12 moles of CO₂ so it means 1 mole of C₆H₆ gives 6 moles of CO₂.

Moles of C₆H₆ from 20 grams is=

Moles= Mass/ Molercular Mass
= 20/78
=.2564 moles of C₆H₆

as we said 1 mole of C₆H₆ gives 6 moles of CO₂
0.2564 moles of C₆H₆ gives (6 * 0.2564) =1.5384 moles of CO₂

Again Moles= Mass/ Molar mass
1.5384 moles= Mass/ 44
Mass= 67.6896 gms or you could say ~68 grams


I think this is how it is.

I hope that would help.

-Sharan

[Schrec42]

thanx for the help. I really appreciate it.


thanks
schrec