chem126: mol of H+ reacted?

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H₃C₆H₃O₇(aq) + 3NaHCO₃(s) --> CO₂(g) + 3H₂O(l) + Na₃C₆H₃O₇(aq)

A student measures 10.98 g of baking soda ( a.k.a. sodium bicarbonate or "NaHCO₃") and adds this to 24. mL of 3.5 M oxalosuccinic acid, H₃C₆H₃O₇ (in an alcoholic solution).

Identify the limiting reagent and calculate the number of moles of CO₂ produced.

Limiting Reagent= NaHCO₃

1.307×10-1 mol of CO₂ are produced.

The temperature of the solution goes from 22.0°C to 7.0°C.
Calculate the temperature change per mole of H+ which reacted.

22 degrees celcius + 273K= 295K
7 degrees celcius + 273K= 280K

295K-280K= 15K

mole of H+ reacted= 3(0.04357mol H₃C₆H₃O₇)= 0.1307mol H+

15K / 0.1307mol H+ = 114.8 K/mol

BUT THIS IS THE WRONG ANSWER, IT IS NOT 114.8 K/mol. HOW COME??

PLEASE HELP A.S.A.P.

thank-you!