zinc acetate dihydrate+tea polyphenols→ZnO NPs

[青苹果]

Could someone please tell me how zinc acetate dihydrate and tea polyphenols react to produce zinc oxide nanoparticles?
I’m really trying to figure it out how much zinc oxide was produced in this reaction，but it's too hard for me
All I know now is that it might be like this： Zn（CH₃COO）2·2H₂O+ C₂₂H₁₈O₁₁ →Zn（OH）2 + C₂H₄O₂ + H₂O +
Zn（OH）2→ZnO+ H₂O

[theresamiera]

I think the correct balanced equation for the reaction between zinc acetate dihydrate (Zn(CH₃COO)₂·2H₂O) and tea polyphenols (C₂₂H₁₈O₁₁) would be:

Zn(CH₃COO)₂·2H₂O + C₂₂H₁₈O₁₁ → Zn(OH)₂ + 2CH₃COOH + H₂O

In this equation, zinc acetate dihydrate and tea polyphenols react to form zinc hydroxide, acetic acid (CH₃COOH), and water.

To produce zinc oxide nanoparticles, further steps would be required. One common method is to heat the zinc hydroxide obtained from the reaction to convert it into zinc oxide. The reaction can be represented as:

Zn(OH)₂ → ZnO + H₂O

[ChenBeier]

The equation is not balanced, what happens to the polyphenol.