Vanadate chemical reaction

[perton]

MnCl₂+2NH₄VO₃. i need to get MnV₂O₆

[ChenBeier]

MnCl₂ + 2 NH₄VO₃ => MnV₂O₆ + 2 NH₄Cl
NH₄Cl => NH₃ + HCl vapour

[FRancoFrias]

To obtain MnV₂O₆ from MnCl₂ and NH₄VO₃, you would need to perform a redox reaction and adjust the stoichiometry accordingly. Here's the balanced chemical equation:

3 MnCl₂ + 5 NH₄VO₃ + 9 H₂O → MnV₂O₆ + 10 NH₄Cl + 6 HCl

In this reaction, 3 moles of MnCl₂ react with 5 moles of NH₄VO₃ to yield 1 mole of MnV₂O₆, along with the formation of 10 moles of NH₄Cl and 6 moles of HCl. It's important to note that this is a balanced equation, meaning that the number of atoms of each element is the same on both sides.

Please exercise caution when working with chemicals and follow appropriate safety measures.

[ChenBeier]

To much nonsense

Your equation isn't balanced and its also no redox reaction.

Which Atom is oxidised and which is reduced? No one

Also 3 MnCl₂ gives MnV₂O₆, what happens to the other 2 Mn

[penaltyshooters]

To obtain MnV₂O₆ from MnCl₂ and NH₄VO₃, you can follow the following steps:

Start by preparing a solution of MnCl₂ by dissolving the compound in water.
Similarly, prepare a solution of NH₄VO₃ by dissolving it in water.
Mix the two solutions together slowly while stirring.
A reaction will occur, resulting in the formation of a precipitate.
Filter the precipitate and wash it with distilled water to remove any impurities.
Dry the obtained solid thoroughly.
The resulting solid is MnV₂O₆, a compound containing manganese in its +5 oxidation state.
Please note that handling chemicals should be done with caution and proper safety measures a small world cup

[ChenBeier]

The resulting solid is MnV₂O₆, a compound containing manganese in its +5 oxidation state

No

I think you mean vanadium. Manganese is still Mn 2+