How do I write this as a balanced chemical equation? I am trying to write the chemical equation reduction of the substituted phenylarsonic acid with dithionite which produces Salvarsan. Check the attachment below to help you out.
I got this far but I don't even think this is even close to being right:
C6AsNH6O6+Na2S2O4+H2O—--->C12H12As2N2O2+Na2SO3+Na2SO4+H2O
Thank you!
Synthetic balanced chemical equation of Arsphenamine(Salvarsan)
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Synthetic balanced chemical equation of Arsphenamine(Salvarsan)
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- ChenBeier
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Re: Synthetic balanced chemical equation of Arsphenamine(Salvarsan)
Dithionite to sulfate
S2O4 2- + 4 H2O => 2 SO4 2- + 8 H+ + 6 e-
Arsenic acid to Salvarsan
2 RAsO3H2 + 8 H+ + 8 e- => RAs=AsR + 6 H2O
Nitrogroup 2 RNO2 + 12 H+ + 12 e- => 2 RNH2 + 4 H2O
Sum Reduction
2 RNO2AsO3H2 + 20 H+ + 20 e - => NH2RAs=AsRNH2 + 10 H2O
KgV of electrons = 60
10 S2O4 2- + 40 H2O => 20 SO4 2- + 80 H+ + 60 e-
6 RNO2AsO3H2 + 60 H+ + 60 e - => 3 NH2RAs=AsRNH2 + 30 H2O
Addition
6 RNO2AsO3H2 + 10 S2O4 2- + 10 H2O => 3 NH2RAs=AsRNH2 + 20 H+ + 20 SO42-
Add sodium
6 RNO2AsO3H2 + 10Na2S2O4 + 10 H2O => 3 NH2RAs=AsRNH2 + 20 NaHSO4
S2O4 2- + 4 H2O => 2 SO4 2- + 8 H+ + 6 e-
Arsenic acid to Salvarsan
2 RAsO3H2 + 8 H+ + 8 e- => RAs=AsR + 6 H2O
Nitrogroup 2 RNO2 + 12 H+ + 12 e- => 2 RNH2 + 4 H2O
Sum Reduction
2 RNO2AsO3H2 + 20 H+ + 20 e - => NH2RAs=AsRNH2 + 10 H2O
KgV of electrons = 60
10 S2O4 2- + 40 H2O => 20 SO4 2- + 80 H+ + 60 e-
6 RNO2AsO3H2 + 60 H+ + 60 e - => 3 NH2RAs=AsRNH2 + 30 H2O
Addition
6 RNO2AsO3H2 + 10 S2O4 2- + 10 H2O => 3 NH2RAs=AsRNH2 + 20 H+ + 20 SO42-
Add sodium
6 RNO2AsO3H2 + 10Na2S2O4 + 10 H2O => 3 NH2RAs=AsRNH2 + 20 NaHSO4
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Re: Synthetic balanced chemical equation of Arsphenamine(Salvarsan)
Thank you so much that was really helpful! I really appreciate it you are a life saver.
I was just wondering what does KgV of electrons mean?
I was just wondering what does KgV of electrons mean?
- ChenBeier
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Re: Synthetic balanced chemical equation of Arsphenamine(Salvarsan)
It is like in Mathematics. 1/2 +1/3 = ?
The kgV ( kleinste gemeinsame Vielfache = least common multiple) is 6 so convert to 3/6 + 2/6 = 5/6
The same you do with the electrons in oxidation and reduction equation.
The kgV ( kleinste gemeinsame Vielfache = least common multiple) is 6 so convert to 3/6 + 2/6 = 5/6
The same you do with the electrons in oxidation and reduction equation.